else-if ladder is a control structure used to check
multiple conditions out of which any single condition must be true.
In else-if ladder, condition by condition are checked, if
any condition is true then statements under the conditional statement is
executed and left all the structure is skipped from the execution.
If no conditions are true then the else part is executed.
Defining of else part is optional in else-if ladder.
|
 |
Note: there should be a space among the if and else.
Difference among the if and else-if ladder:
#include<stdio.h>
void main()
{
if(10<20 if="" ne="" printf="">80)
printf("\nTwo");
if(20!=40)
printf("\nFour");
}
Output:
One
Four
#include
void main()
{
if(10<20 else="" if="" ne="" printf="">80)
printf("\nTwo");
else if(20!=40)
printf("\nFour");
}
Output:
One
Specification1:
Accept any character from the keyboard and print whether the
given character is a vowel, consonant, digit or special symbol.
Program:
#include<stdio.h>
void main()
{
char ch;
printf("Enter any character:");
scanf("%c",&ch);
if(ch==’a’ || ch== ‘e’ || ch==’i’ || ch==’o’ || ch==’u’)
printf("Vowel");
else if(ch>=’b’ && ch<=’z’)
printf("Consonant");
else if(ch>=’0’ && ch<=’9’)
printf("Digit");
else
printf("Special symbol");
}
Execution1:
Enter any character: e
Vowel
Execution2:
Enter any character: p
Consonant
Execution3:
Enter any character: 8
Digit
Execution4:
Enter any character: $
Special symbol
Specification2:
Accept the type of customer, principle amount, period of
time and print the simple interest and the total amount must be paid to the
financer.
Here the interest rates per month are 1% for employees, 2%
for farmers, 3% for business people and 5 for others
Logic: S.I= P*T*R/100
Program:
#include<stdio.h>
void main()
{
long int amount;
int time,ch;
float si,total;
printf("1. Employee\n2. Farmer\n3. Business Person\n4. Other\nEnter your choice 1..4:");
scanf("%d",&ch);
printf("Principle Amount:");
scanf("%ld",&amount);
printf("Period of time in months:");
scanf("%d",&time);
if(ch==1)
si=(float)amount*time*1/100;
else if(ch==2)
si=(float)amount*time*2/100;
else if(ch==3)
si=(float)amount*time*3/100;
else
si=(float)amount*time*5/100;
total=amount+si;
printf("Amount %ld",amount);
printf("\nSimple Interest %f",si);
printf("\nTotal amount %f",total);
}
Execution:
1. Employee
2. Farmer
3. Business Person
4. Other
Enter your choice 1..4: 3
Principle Amount: 52500
Period of time in months: 5
Amount 52500
Simple interest 7875
Total amount 60375
Specification3:
Enter any number and print whether the given number is a
single digit, two digit, three digit, biggest or smallest number.
#include<stdio.h>
void main()
{
Incase of simple if
if(n>=-9 && n<=9)
printf("Sigle digit number");
if((n>=-99&&n<=10) || (n>=10&&n<=99))
printf("Two digit number");
if((n>=-999&&n<=-100) || (n>=100&&n<=999))
printf("Three digit number");
if(n>999)
printf("Biggest number");
if(n<-999 any="" d="" if="" int="" mallest="" n="" nter="" number:="" number="" printf="" scanf="">=-9 && n<=9)
printf("Single digit number");
else if(n>=-99 && n<=99)
printf("Two digit number");
else if(n>=-999 && n<=999)
printf("Three digit number");
else if(n>999)
printf("Biggest number");
else
printf("Smallest number");
}
Execution1:
Enter any number: 25
Two digit number
Execution2:
Enter any number: -425
Three digit number
Execution3:
Enter any number: 1500
Biggest number
Specification4:
Accept the salary of an employee and print the HRA, DA and
gross salary according to the following table.
|
Salary |
HRA |
DA |
|
More than 25000 |
15% |
55% |
|
19001 to 25000 |
13% |
42% |
|
10001 to 19000 |
12% |
35% |
|
1 to 10000 |
5% |
15% |
Program:
#include<stdio.h>
void main()
{
long int sal;
float hra,da,gross;
printf("Enter the salary:");
scanf("%ld",&sal);
if(sal>25000)
{
hra=(float)sal*15/100;
da=(float)sal*55/100;
}
else if(sal>=19001)
{
hra=(float)sal*13/100;
da=(float)sal*42/100;
}
else if(sal>=10001)
{
hra=(float)sal*12/100;
da=(float)sal*35/100;
}
else
{
hra=(float)sal*5/100;
da=(float)sal*15/100;
}
gross=sal+hra+da;
printf("Salary details:\n");
printf("Salary %ld",sal);
printf("\n House Rent Allowance %f",hra);
printf("\n Dearness Allowance %f",da);
printf("\n Gross salary %f",gross);
}
Execution1:
Enter the salary: 21500
Salary details:
Salary 21500
House Rent Allowance 2795.000000
Dearness Allowance 9030.000000
Gross salary 33325
Specification5:
Accept the type of electrical connection, present month
reading, previous month reading and print the number of units and bill
according to the following table.
|
Type of connection |
Units |
Charge/unit |
customer charges |
|
Domestic |
More than 500 |
6.25 |
45 |
|
301-500 |
6.00 |
45 |
|
|
201-300 |
4.75 |
40 |
|
|
101-200 |
3.05 |
35 |
|
|
51-100 |
2.80 |
30 |
|
|
0-50 |
1.45 |
25 |
|
|
Commercial |
More than 100 |
6.50 |
40 |
|
51-100 |
6.20 |
35 |
|
|
0-50 |
3.85 |
30 |
|
|
|
More than 200 |
4.00 |
40 |
|
0-200 |
2.00 |
40 |
Program:
#include<stdio.h>
void main()
{
char type;
int cmr,pmr,nu,cch;
float bill;
printf("Enter the type of connection d/c/t:");
scanf("%c",type);
printf("Enter the current month meter reading:");
scanf("%d",&cmr);
printf("Enter the previous month meter reading:");
scanf("%d",&pmr);
nu=cmr-pmr;
if(type==’d’)
{
if(nu>=500)
{
bill=nu*6.25;
cch=45;
}
else if(nu>=301)
{
bill=nu*6.00;
cch=45;
}
else if(nu>=201)
{
bill=nu*4.75;
cch=40;
}
else if(nu>=101)
{
bill=nu*3.05;
cch=35;
}
else if(nu>=51)
{
bill=nu*2.80;
cch=30;
}
else
{
bill=nu*1.45;
cch=25;
}
}
else if(type==’c’)
{
if(nu>100)
{
bill=nu*6.50;
cch=40;
}
else if(nu>=51)
{
bill=nu*6.20;
cch=35;
}
else
{
bill=nu*3.85;
cch=30;
}
}
else if(type==’t’)
{
if(nu>200)
{
bill=nu*4.00;
cch=40;
}
else
{
bill=nu*2.00;
cch=40;
}
}
printf("No.of units consumed %d",nu);
printf("\nbill %f",bill);
printf("\nCustomer charges %d",cch);
printf("\nTotal bill %f",bill+cch);
}
Execution1:
Enter the type of connection d/c/t: d
Enter the current month meter
reading: 350
Enter the previous month
meter reading: 210
No.of units consumed: 140
bill 427.000000
Customer charges: 35
Total bill 462.000000
Summery:
- Simple
if control structure is used to check multiple conditions, out of which
any number of conditions may be true.
- if-else
is used to solve a problem which has only two conditions to check, out of
which only a single condition must be true.
- else-if
ladder is used to check multiple conditions, out of which only a single may
be true.
0 comments:
Post a Comment